当input file 状态更改的时候发送ajax
Published
2023-03-03
浏览次数 : 113
$(document).ready(function() {
// Get the input file element
var inputFile = $('input[type="file"]');
// Bind the change event handler to the input file element
inputFile.change(function() {
// Construct a FormData object to send with the request
var formData = new FormData();
formData.append('file', inputFile[0].files[0]);
// Send the AJAX request
$.ajax({
url: 'upload.php', // Replace with your own endpoint
type: 'POST',
data: formData,
processData: false,
contentType: false,
success: function(response) {
console.log('File uploaded successfully:', response);
},
error: function(jqXHR, textStatus, errorThrown) {
console.log('Error uploading file:', textStatus, errorThrown);
}
});
});
});
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